A 0.0111-mol sample of urea, NH2CONH2, contains Question 10 options: 6.02 × 1023 molecules. 2.67 × 1022 mole?
Update:
A 0.0111-mol sample of urea, NH2CONH2, contains
6.02 × 1023 molecules.
2.67 × 1022 molecules.
5.35 × 1022 atoms.
1.11 × 1024 atoms.
2.67 × 1023 atoms.
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Your question got cut off. Here is the relevant calculation:
0.0111 mol times 6.022 x 10^23 molecules / mol = 6.68 x 10^21 molecules
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