Need some help... Can someone tell how to solve this?
Is it: 8^(x*2) = 4x - 1 ?
Ok, you can bring down that exponent by taking the log of both sides:
ln(8^(x*2)) = ln(4x - 1)
(x*2)*ln(8) = ln(4x - 1)
x*2 = ln(4x - 1) / ln(8)
x = ln(4x - 1) / (2*ln(8))
Copyright © 2024 1QUIZZ.COM - All rights reserved.
Answers & Comments
Verified answer
Is it: 8^(x*2) = 4x - 1 ?
Ok, you can bring down that exponent by taking the log of both sides:
ln(8^(x*2)) = ln(4x - 1)
(x*2)*ln(8) = ln(4x - 1)
x*2 = ln(4x - 1) / ln(8)
x = ln(4x - 1) / (2*ln(8))