466 g of water is heated from 8.50°C to 74.60°C. What is the heat absorbed (in kJ) by the water.?
Help! im studying for a chem test and I cannot figure out what I keep doing wrong. I get the concept but I cannot seem to get the answers to align.
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dH = m C dT
dH = (466 grams) (4.184 J/g-K) (74.60 - 8.50)
dH = (466 grams) (4.184 J/g-K) (66.1 C rise)
dH = 126,678 nJoules
aka 126.678 kJ
your answer, rounded to 3 sig figs is
127 kJ is absorbed
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p.s.
it is also = 30.8 kilocalories