I take it you mean √(3x-2) +2 = 0 and not something like
√(3x) - 2 +2 = 0
Get the radical by itself, then square both sides to get rid of the radical. Then solve for x.
√(3x-2) +2 = 0
√(3x-2) = -2
3x - 2 = 4
I'm sure you can take it from there
â(3x-2) +2 = 0 subtract 2 from each side
â(3x-2)=-2 square both sides
3x-2=4 add 2 to each side
3x=6 divide both sides by 3
x=2
check
â(2*2-2)+2=0
â4+2=0
There is no solution!
â3x-2 +2 = 0
â3x=0
x=0
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Verified answer
I take it you mean √(3x-2) +2 = 0 and not something like
√(3x) - 2 +2 = 0
Get the radical by itself, then square both sides to get rid of the radical. Then solve for x.
√(3x-2) +2 = 0
√(3x-2) = -2
3x - 2 = 4
I'm sure you can take it from there
â(3x-2) +2 = 0 subtract 2 from each side
â(3x-2)=-2 square both sides
3x-2=4 add 2 to each side
3x=6 divide both sides by 3
x=2
check
â(2*2-2)+2=0
â4+2=0
There is no solution!
â3x-2 +2 = 0
â3x=0
x=0