the problem: http://s9.postimage.org/ycdjxuwyj/Screen_shot_2012...
explaining it step by step would help. lol :) please and thank you!
what you need to do is multiply by its conjugate on the numerator and denominator
√3/( 2-4√5)* (2+4√5)/ (2+4√5)
= √3* (2+4√5)/ (4- 16*5)
(a+b) (a-b)= a^2-b^2
= (2√3+4√15)/ -76
â(3)/(2-4â5)
â(3)/2(1-2â5)
(â3+2â15)/2(1-20)
-(â3+2â15)/38
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Verified answer
what you need to do is multiply by its conjugate on the numerator and denominator
√3/( 2-4√5)* (2+4√5)/ (2+4√5)
= √3* (2+4√5)/ (4- 16*5)
(a+b) (a-b)= a^2-b^2
= (2√3+4√15)/ -76
â(3)/(2-4â5)
â(3)/2(1-2â5)
(â3+2â15)/2(1-20)
-(â3+2â15)/38