2 N2H4(liq) + N2O4 (g) → 3 N2 (g) + 4 H2O(g) + heat?
Liquid hydrazine (N2H4) and dinitrogen tetroxide (N2O4). The two chemicals ignite on contact to release very large amounts of energy as heat:
2 N2H4(liq) + N2O4 (g) → 3 N2 (g) + 4 H2O(g) + heat
If 21.4 g of hydrazine reacts completely with dinitrogen tetroxide and the gaseous products are collected at 27°C in a 250.0 L tank, what is the pressure in the tank?
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2N2H4(l) + N2O4(g) --> 3N2(g) + 4H2O(g) ........ ΔH is negative
21.4g .........excess ....... ? .............?
21.4 g N2H4 x (1 mol N2H4 / 32.0 g N2H4) x (7 mol prod / 2 mol N2H4) = 2.34 moles of gaseous products
PV = nRT
P = nRT / V
P = 2.34 mol x 0.0821 Latm/molK x 300.K / 250.0L
P = 0.231 atm