Verified answer

Limit (x approaches 3) 2x - 1 = 5. Since f(x) = 5 by definition AT x = 3 then the function is continuous.

We need to examine the continuity at x=3.

f(x) is defined at x=3

lim f(x) as x approaches 3 exists

f(3)= 2x-1 = 2(3)-1 =5

So, f is continuous at x=3

f is continuous for all x.