Verified answer

y = 5x

2x + 2(5x) = 17 - 5x

17x = 17

x = 1

y = 5

(1, 5)

Isolate for y in both equations.

y-x = 4x

y = 4x + x

y = 5X <- Equation 1

2x+2y = 17-y

2y = 17-y-2x

2y+y = 17-2x

3y = 17-2x

y = (17/3)-(2/3)x <- Equation 2

Set equation 1 equal to equation 2 and solve for x

5x = (17/3)-(2/3)x

5x+(2/3)x = 17/3

(17/3)x = 17/3

x = 1

Substitute x=1 into either equation 1 or equation 2 (note, you must substitute it back into the original equation). I will substitute it into equation 1 for simplicity.

y-x = 4x

y-(1) = 4(1)

y-1 = 4

y=5

Therefore, (x,y) = (1,5)

Hope this helps!