The equation: 5x^3 - 320x = 0 Dividing by using x during, x [ 5x^2 - 320 ] = 0 So x = 0, or 5x^2 - 320 = 0 For 5x^2 - 320 = 0, rearranging supplies x^2 = 320/5 = sixty 4 x = sqrt[sixty 4] = 8 or -8 consequently x = 0, x = 8, or x = -8 P.S. it quite is a cubic equation, so it has 3 suggestions.
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√ (5 - x) - 3 = 0
√ (5 - x) = 3
5 - x = 9
- 4 = x
Could it be that should read as :-
√ (5 - x) - 3 = 0
√ (5 - x) = 3
5 - x = 9
- 4 = x
The equation: 5x^3 - 320x = 0 Dividing by using x during, x [ 5x^2 - 320 ] = 0 So x = 0, or 5x^2 - 320 = 0 For 5x^2 - 320 = 0, rearranging supplies x^2 = 320/5 = sixty 4 x = sqrt[sixty 4] = 8 or -8 consequently x = 0, x = 8, or x = -8 P.S. it quite is a cubic equation, so it has 3 suggestions.
sq rt 5-x = 3
(sq rt 5-x)=3)^2
5-x=9
-x=4
x=-4 5-(-4)= 5+4=9 msqrt 9=3