(x + y + 2) ÷ 2 = (x + y ÷ 4) = 2, x + y + 1 = 3

Solution:

x = 2, y = 0

If you meant (x+y+2)/2 = (x+y)/4 = 2x+y+1 = 3,

the parentheses were REQUIRED.

However, you have written three equations in two unknowns,

and there is no combo of x and y that will work for all three.

Maybe you should have omitted the equals sign just after the 4 ?

In that case, I would agree with Cidyah's answer, x = 6 and y = -10.

(x+y+2)/2 = (x+y)/4

2(x+y+2)/4 = (x+y)/4

2(x+y+2) = x+y

2x+2y+4 = x+y

x+y = -4 ------(1)

2x+y+1=3

2x+y = 2 ------(2)

subtract (2) from (1)

-x = -6

x= 6

x+y=-4

6+y=-4

y=-10

x=6

y=-10

x + y + 2/2 = 3

2x + y + 1 = 3

Solve the system of equations.

x + y + 1 = 3

x + y = 2

x = 2 - y

2(2 - y) + y + 1 = 3

4 - 2y + y + 1 = 3

-y + 5 = 3

-y = -2

y = 2

x + 2 = 2

x = 0

See is x and y work for the third equation.

x + y/4 = 3

0 + 2/4 = 3

1/2 = 3 is false

The system of three equations has no solution.