take care of the < or > indications as being the comparable an = sign and remedy such as you may an equality6d7dbf7aa71ff7a1d7c78c6b13b26a93 The e6d7dbf7aa71ff7a1d7c78c6b13b26a93ception is that if there's a detrimental element: 6d7dbf7aa71ff7a1d7c78c6b13b26a936d7dbf7aa71ff7a1d7c78c6b13b26a936d7dbf7aa71ff7a1d7c78c6b13b26a936d7dbf7aa71ff7a1d7c78c6b13b26a936d7dbf7aa71ff7a1d7c78c6b13b26a93 > 4 [6d7dbf7aa71ff7a1d7c78c6b13b26a936d7dbf7aa71ff7a1d7c78c6b13b26a936d7dbf7aa71ff7a1d7c78c6b13b26a936d7dbf7aa71ff7a1d7c78c6b13b26a936d7dbf7aa71ff7a1d7c78c6b13b26a93] (-2)x 6d7dbf7aa71ff7a1d7c78c6b13b26a936d7dbf7aa71ff7a1d7c78c6b13b26a93 > 46d7dbf7aa71ff7a1d7c78c6b13b26a936d7dbf7aa71ff7a1d7c78c6b13b26a936d7dbf7aa71ff7a1d7c78c6b13b26a93 then (-2)x > 6d7dbf7aa71ff7a1d7c78c6b13b26a936d7dbf7aa71ff7a1d7c78c6b13b26a93 (-2)x it is not true6d7dbf7aa71ff7a1d7c78c6b13b26a93 (-2)x < 6d7dbf7aa71ff7a1d7c78c6b13b26a936d7dbf7aa71ff7a1d7c78c6b13b26a93 is correct6d7dbf7aa71ff7a1d7c78c6b13b26a93 in case you divide by a detrimental number6d7dbf7aa71ff7a1d7c78c6b13b26a93 then the <> indications could desire to be reversed ><(-2)x
Answers & Comments
Verified answer
√(x + 9 ) = 4
x + 9 = 4^2
x = 16 - 9 = 7
if your question is √ ( 8 - x + 6 ) = 4
then
√ ( 14 - x ) = 4
( 14 - x ) = 4^2
x = 14 - 16 = -2
3.....√ ( 2x + 20) + 2 = x
√ ( 2x + 20 ) = x - 2
squaring on both sides
2x + 20 = x^2 - 4x + 4
x^2 - 6x - 16 = 0
( x - 8 ) ( x + 2 ) = 0
x - 8 = 0 or x + 2 = 0
x = 8 or x = - 2
but x = 8 is the extraneous root since x = -2 doesn't satisfies the equation
take care of the < or > indications as being the comparable an = sign and remedy such as you may an equality6d7dbf7aa71ff7a1d7c78c6b13b26a93 The e6d7dbf7aa71ff7a1d7c78c6b13b26a93ception is that if there's a detrimental element: 6d7dbf7aa71ff7a1d7c78c6b13b26a936d7dbf7aa71ff7a1d7c78c6b13b26a936d7dbf7aa71ff7a1d7c78c6b13b26a936d7dbf7aa71ff7a1d7c78c6b13b26a936d7dbf7aa71ff7a1d7c78c6b13b26a93 > 4 [6d7dbf7aa71ff7a1d7c78c6b13b26a936d7dbf7aa71ff7a1d7c78c6b13b26a936d7dbf7aa71ff7a1d7c78c6b13b26a936d7dbf7aa71ff7a1d7c78c6b13b26a936d7dbf7aa71ff7a1d7c78c6b13b26a93] (-2)x 6d7dbf7aa71ff7a1d7c78c6b13b26a936d7dbf7aa71ff7a1d7c78c6b13b26a93 > 46d7dbf7aa71ff7a1d7c78c6b13b26a936d7dbf7aa71ff7a1d7c78c6b13b26a936d7dbf7aa71ff7a1d7c78c6b13b26a93 then (-2)x > 6d7dbf7aa71ff7a1d7c78c6b13b26a936d7dbf7aa71ff7a1d7c78c6b13b26a93 (-2)x it is not true6d7dbf7aa71ff7a1d7c78c6b13b26a93 (-2)x < 6d7dbf7aa71ff7a1d7c78c6b13b26a936d7dbf7aa71ff7a1d7c78c6b13b26a93 is correct6d7dbf7aa71ff7a1d7c78c6b13b26a93 in case you divide by a detrimental number6d7dbf7aa71ff7a1d7c78c6b13b26a93 then the <> indications could desire to be reversed ><(-2)x
Can you edit the question to include brackets?
I don't know if you mean √x + 9 or √(x+9).