x minus one quantity squared, minus two
x intercepts of (x-1)²-2
(x – 1)² = 2
(x – 1) = ± √2
x = 1 ± √2
x-intercepts { (1 – √2, 0), (1 + √2, 0) }
The x-intercepts of y = x² -2 are where y = 0.
So we have:
0 = x² - 2
Add 2 to both sides to get:
2 = x²
Now take the square root of both sides:
x = +/- â2
So the x intercepts are x = â2 and x = -â2.
Let f(x) = (x-1)² - 2
then x-intercepts are where f(x) = 0
f(x) = 0
(x-1)² - 2 = 0
(x-1)² = 2
x - 1 = 屉2
x = 1 ± â2
let y=(x-1)^2-2
to get y intercept y=0
therefore (x-1)^2-2=0
(x-1)^2=2
x-1=+root 2 / - root 2
x=1+root 2,1-root 2
x^2-2x+1-2
x^2-2x+1
(x-1)(x-1)
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Verified answer
x intercepts of (x-1)²-2
(x – 1)² = 2
(x – 1) = ± √2
x = 1 ± √2
x-intercepts { (1 – √2, 0), (1 + √2, 0) }
The x-intercepts of y = x² -2 are where y = 0.
So we have:
0 = x² - 2
Add 2 to both sides to get:
2 = x²
Now take the square root of both sides:
x = +/- â2
So the x intercepts are x = â2 and x = -â2.
Let f(x) = (x-1)² - 2
then x-intercepts are where f(x) = 0
f(x) = 0
(x-1)² - 2 = 0
(x-1)² = 2
x - 1 = 屉2
x = 1 ± â2
let y=(x-1)^2-2
to get y intercept y=0
therefore (x-1)^2-2=0
(x-1)^2=2
x-1=+root 2 / - root 2
x=1+root 2,1-root 2
x^2-2x+1-2
x^2-2x+1
(x-1)(x-1)