Could anyone help me with this?
Identify the center and radius of the circle given by the equation
x²+y²-10x+4y-7=0
I cannot figure out what I'm doing wrong. The final answer supposed to be Center: (5,-2) Radius 6
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Verified answer
Complete the square: x² - 10x + 25 = -y² - 4y + 7 + 25
Factor: (x - 5)² + y² + 4y = 36
Complete the Square again: (x - 5)² + y² + 4y + 4 = 36
Factor: (x - 5)² + (y + 2)² = 36
Radius: 6
Center: (5,-2)
we have to complete the square... x^2-10x ... divide 10 by 2 = 5 add and subtract the square 25
Then it is x^2 -10x +25 - 25 = (x-5)^2 -25
Now complete the square fo y^2 + 4y... divide 4 by 2 = 2 add and subtract the square 4
Then it is y^2 + 4y +4 -4 = (y+2)^2 -4
Then the equation is (x-5)^2 -25 + (y+2)^2 - 4 - 7 = 0 ==> (x-5)^2 +(y+2)^2 = 36 =6^2
The the center is (5,-2) and the radius is 6 Ok!
First, group the xs and ys together and add 7 to each side:
x^2 - 10x + y^2 + 4y = 7
Complete the square for x and y:
X^2 - 10x + 25 + y^2 + 4y + 4 = 36
Turn them into square binomials to finish the problem:
(x - 5)^2 + (y + 2)^2 = 36
There ya go.
Miss Kristin
x²+y²-10x+4y-7=0
complete the square for both x and y
x² - 10x = (x -5)² -5² and y² +4y = (x +2)² -2²
(x² -10x + 25) +(y² +4y +4) - 29 -7 =0
(x -5)² +(y +2)² = r² = 36
so (-5,2) is the center and r =6