A golf ball with an initial angle of 30° lands exactly 220 m down the range on a level course.?
A golf ball with an initial angle of 30° lands exactly 220 m down the range on a level course.
Neglecting air friction, what initial speed would achieve this result?
Using the speed determined in item (a), find the maximum height reached by the ball.
Please Explain.
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Use the range equation
d =V^2 sin (2 theta) / g
V^2 = d g / sin (2 theta)
V = sqrt [ d g / sin (2 theta) ]
= sqrt [ 220 x 9.8 / sin (2 x 30) ]
V = 49.89m/.s
Use maximum height formula
h = V^2 sin^2(theta) /2g
= 49.89^2 sin^2 (30) /.(2 x 9.8)
=31.72 meters