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Update:Write the slope-intercept equation for the line that passes through (-14, -3) and is perpendicular to -7x – 4y = -4
sorry there was a part missing, many thanks for your help.....
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Answers & Comments
-7x - 4y = -4 -4y = 7x - 4 4y = -7x + 4 y = (-7x + 4) / 4 y = -(7/4)x + a million Slope of that line is -7/4, so a line perpendicular to that would have a slope it particularly is the destructive reciprocal of -7/4, i.e. 4/7, so the hot line is y = (4/7)x + b, which passes via (-14, -3), so we've: -3 = (4/7)(-14) + b -3 = -8 + b b = -3 + 8 b = 5 So the hot line is y = (4/7)x + 5
slope intercept equation is y = mx + b
if a line is perpendicular to another, their slopes are the negative inverse of each other
m = - 1/m
perpendicular line is -7x - 4y = -4?<<<<<<***edit for additional info.***
-4y = 7x -4
y = -7/4x +1>>>>>>perpendicular slope is -7/4
slope of the equation you are looking for is 4/7 and it passes through point (-14, -3)
y = mx + b
-3 = (4/7)-14 + b
- 3 = -8 + b
b = 5, m = 4/7
y = (4/7)x + 5