whats the answer?
a. cos 4 θ
b. cos 8 θ
c. sin 4 θ
d. sin 8 θ
2 sin nθ cos nθ = sin 2nθ
here n = 4
then
2 sin 4θ cos 4θ = sin 2*4 θ = sin 8θ
.. sin( 2 [4θ] ) = 2 sin[4θ] cos[4θ]
Ans: D â
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2 sin nθ cos nθ = sin 2nθ
here n = 4
then
2 sin 4θ cos 4θ = sin 2*4 θ = sin 8θ
.. sin( 2 [4θ] ) = 2 sin[4θ] cos[4θ]
Ans: D â