Women’s heights are normally distributed with mean 63.6 in and standard deviation of 2.5 in. A social organiza?
Women’s heights are normally distributed with mean 63.6 in and standard deviation of 2.5 in. A social organization for tall people has requirement that women must be at least 69 in tall. What percentage of women meet that requirement?
The percentage of women that are taller than 69 in is ___% ( round to two decimal places as needed)
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z = ( x - μ ) / σ = 2.16
P (2.16 < z) = 0.0154 = 1.54% <-------
z = (X-Mean)/SD
z = (69-63.6)/2.5 = + 2.16
The area under the standard normal curve right to the z value indicates the required proportion.
Required percentage = 100*P(X>69)
= 100*P(z > 2.16)
= 100*0.0154
= 1.54%