Why is 25°C standard for solving delta G?

I'm trying to find delta G (Gibbs free energy) at "typical conditions in the muscle cells." So nonstandard conditions.

∆G = ∆G° + R∙T∙ln([ADP]∙[P]/[ATP])

Why would my professor use 25°C (273 Kelvin) in the equation instead of actual body temperature (98 Farenheit or 37 degrees Celcius)???

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