A)increase by about 20%
B)remain the same
C)decrease by 1/3
D)triple
I'm stuck between A and D. Can someone please help me?
using Charles law :
V1/T1 = V2/T2
here temperature should be in Kelvin....
where V1 = V
T1 = 30 + 273 = 303 K
T2 = 90 + 273 = 363 K
V2 = ?
V/303 = V2/363
V2 = V/303 X 363 = 1.198V
% increase = V2-V1/V X 100 = 1.198V - V / V X 100 = 0.198 X 100 = 19.8%
so A is the answer
feel free to ask any question
the quantity will enhance using fact the temperature is going up, yet to get the quantity you should transform the temperatures to Kelvin so the respond is (ninety + 273) / ( 30 + 273) = 363/303 = a million.2 so the quantity extra suitable via 20%
Formula pV=nRT so if p and n are constant the volume is proportional to absolute temperature
if t=30c so T=273+30=303C and t=90C T=273+90C=363C
V(90)/V(30) = 363/303=1.2 =120%
so answer 20% A s correct
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Verified answer
using Charles law :
V1/T1 = V2/T2
here temperature should be in Kelvin....
where V1 = V
T1 = 30 + 273 = 303 K
T2 = 90 + 273 = 363 K
V2 = ?
V/303 = V2/363
V2 = V/303 X 363 = 1.198V
% increase = V2-V1/V X 100 = 1.198V - V / V X 100 = 0.198 X 100 = 19.8%
so A is the answer
feel free to ask any question
the quantity will enhance using fact the temperature is going up, yet to get the quantity you should transform the temperatures to Kelvin so the respond is (ninety + 273) / ( 30 + 273) = 363/303 = a million.2 so the quantity extra suitable via 20%
Formula pV=nRT so if p and n are constant the volume is proportional to absolute temperature
if t=30c so T=273+30=303C and t=90C T=273+90C=363C
V(90)/V(30) = 363/303=1.2 =120%
so answer 20% A s correct