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Since 6x^3 – 29x^2 – 6x + 5 factors as (2x+1)(3x-1)(x-5), the zeroes are x=-1/2, 1/3, and 5.
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Since 6x^3 – 29x^2 – 6x + 5 factors as (2x+1)(3x-1)(x-5), the zeroes are x=-1/2, 1/3, and 5.