When you take a bath, how many kilograms of hot water (48.3°C) must you mix with cold water (13.6°C) so that t?
When you take a bath, how many kilograms of hot water (48.3°C) must you mix with cold water (13.6°C) so that the temperature of the bath is 34.7°C? The total mass of water (hot plus cold) is 189 kg. Ignore any heat flow between the water and its external surroundings.
this is making me mad
mass(34.7-13.6)4.18=189000(4.18)(48.3-34.7)
what am i doing wrong
Update:x(34.7-13.6)4.18= 189000(4.18)(48.3-34.7) right?
More Questions From This User See All
Answers & Comments
Verified answer
Here, Mh=x,Mc=189-x,del theta 1=(48.3-34.7)K=13.6K,del theta 2=(34.7-13.6)K=21.1K
So, Mh*S*DT1=Mc*S*DT2 or, Mh*DT1=Mc*DT2 or, Mh=Mc(DT2/DT1) or, x=1.55(189-x) or, 2.55x=293.23 or, x=114.99
So you should mix 114.99 kg hot water.