When a proton has a velocity v = (2i+5j) × 106 m/s, it experiences a force?
When a proton has a velocity v = (2i+5j) × 106 m/s, it experiences a force F = −1.8E-13 N. When its velocity is along the +z axis, it experiences a force along the +x axis. What is the magnetic field?
( ?? i + ?? j + ??k ) T
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I want to solve this problem but there is some missing information.
♦"When its velocity is along the +z axis, it experiences a force along the +x axis"
This establishes that the x-component of the B field is zero ( B is directed in the y-z plane ) and that the y-component of the field is negative.
♦"When a proton has a velocity v = (2i+5j) × 106 m/s, it experiences a force F = −1.8E-13 N."
A force of F = −1.8 × 10^-13 N along which axis?