The small calorie or gram calorie (symbol: cal)[2] approximates the energy needed to increase the temperature of 1 gram of water by 1 °C. This is about 4.2 joule
So, the number of calories = 51.3 (100 - 0) = 5130
The equivalent number of joules = 5130 x 4.2 = 21,546 j or 21.546 kj
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The small calorie or gram calorie (symbol: cal)[2] approximates the energy needed to increase the temperature of 1 gram of water by 1 °C. This is about 4.2 joule
So, the number of calories = 51.3 (100 - 0) = 5130
The equivalent number of joules = 5130 x 4.2 = 21,546 j or 21.546 kj