Equation:
CH4 +2O2 → CO2 + 2H2O
1mol CH4 will produce 1 mol CO2
Molar mass CH4 = 12+4 = 16g/mol
Molar mass CO2 = 12+32 = 44g/mol
5.6*10^-3g CH4 will produce 44/16*(5.6*10^-3) = 1.54*10^-2g CO2
CH4 + 2O2 -> CO2 +2 H2O
And now let's think:
For 16^(10-3)g of methane(1mmol) ------------------------- 44^(10-3)g CO2(1mmol)
5.6^(10-3)g X
X= 5.6^(10-3)g*44^(10-3)g/16^(10-3)g = 15.4^(10-3)g
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Verified answer
Equation:
CH4 +2O2 → CO2 + 2H2O
1mol CH4 will produce 1 mol CO2
Molar mass CH4 = 12+4 = 16g/mol
Molar mass CO2 = 12+32 = 44g/mol
5.6*10^-3g CH4 will produce 44/16*(5.6*10^-3) = 1.54*10^-2g CO2
CH4 + 2O2 -> CO2 +2 H2O
And now let's think:
For 16^(10-3)g of methane(1mmol) ------------------------- 44^(10-3)g CO2(1mmol)
5.6^(10-3)g X
X= 5.6^(10-3)g*44^(10-3)g/16^(10-3)g = 15.4^(10-3)g