at the beginning, u have have been given to knw this: " a million mole of any gas occupies 24,000cm^3 at s.t.p" So, we've got have been given to discover the quantity occupied through 6.4g of sulphur dioxide at s.t.p. Now this suggests that we might desire to constantly convert that 6.4g of sulphur dioxide into moles. In different words, we are able to might desire to first discover out the variety of moles in 6.4g of sulphur dioxide. with a view to try this -> Mass / Relative formulation Mass wherein the Mass is 6.4g and the Relative formulation Mass is 64g (32 + 2(sixteen)). So, while u divide that u get, 0.a million moles. Now shall we pass decrease back to the section the place we mentioned a million mole of a gas occupies 24,000 cm^3 of quantity. which means 0.a million mole of a gas will occupy : 0.a million*24,000cm^3 and that's 2400cm^3. Thats the respond. and that i see its no longer in the recommendations that u have provide. yet i'm rather particular thats the respond for this question. GoodLuck!!
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First you have to get the number of moles present.
No. of moles = mass present/relative molecular mass.
Represent No. of moles with ''n''.
n = 9.65/64
we'll take the relative molecular mass of sulfur dioxide to be 64g but its actually 63.961899934 g.
You find this using the periodic table.
n = 0.15078125
Now we use the formula ''pV=nRT'' to find the volume.
p = 785 mmHg = 785 X 133.3 (to get value in pascals) = 104640.5 Pa
V= V
n = 0.15078125
R = real gas constant which equals = 8.31
T = 12°C + 273 (to convert value to Kelvin Scale) = 285 K
sub in :
(104640.5)(V)=(0.15078125)(8.31)(285)
(104640.5)(V)=357.10277343
V= 357.10277343/104640.5
V = 0.0034126631 Liters
Convert Liters to cm(cubed) by multiplying by 1000 (1L = 1000cm3)
V = 3.4126631cm3
at the beginning, u have have been given to knw this: " a million mole of any gas occupies 24,000cm^3 at s.t.p" So, we've got have been given to discover the quantity occupied through 6.4g of sulphur dioxide at s.t.p. Now this suggests that we might desire to constantly convert that 6.4g of sulphur dioxide into moles. In different words, we are able to might desire to first discover out the variety of moles in 6.4g of sulphur dioxide. with a view to try this -> Mass / Relative formulation Mass wherein the Mass is 6.4g and the Relative formulation Mass is 64g (32 + 2(sixteen)). So, while u divide that u get, 0.a million moles. Now shall we pass decrease back to the section the place we mentioned a million mole of a gas occupies 24,000 cm^3 of quantity. which means 0.a million mole of a gas will occupy : 0.a million*24,000cm^3 and that's 2400cm^3. Thats the respond. and that i see its no longer in the recommendations that u have provide. yet i'm rather particular thats the respond for this question. GoodLuck!!