In an experiment, 23.5 g of metal was heated to 98.0°C and then quickly transferred to 150.0 g of water in a calorimeter. The initial temperature of the water was 24.0°C, and the final temperature after the addition of the metal was 32.5°C. Assume the calorimeter behaves ideally and does not absorb or release heat.
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(4.184 J/g·°C) x (150.0 g) x (32.5°C - 24.0°C) = 5334.6 J gained by the water (and lost by the metal)
(5334.6 J) / (23.5 g) / (98.0°C - 32.5°C) = 3.47 J/g·°C
[That's an extremely high specific heat capacity for any metal that does not react with water. Are you sure about the given numbers?]