enable's initiate with 3). Sin is destructive and cos is helpful, so the terminal arm could be in quadrant 4. Draw an axis, and stick a terminal arm in quadrant 4. Draw the reference triangle. If sin is -12/13, then the hypotenuse of the ref. triangle is 13. Which area of the triangle is 12? what's the size of the third area (you will could calculate this) With the lengths of all 3 facets of the triangle labelled, you may genuinely record the values of all the trig purposes.
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Verified answer
cos[Tan^-1√3-Sin^-1(1/2)]
arctan(1/√3) = π/6
arcsin(1/2) = π/6
So that :
cos( π/6 - π/6 )
= cos( 0 )
= 1
Answer : B
enable's initiate with 3). Sin is destructive and cos is helpful, so the terminal arm could be in quadrant 4. Draw an axis, and stick a terminal arm in quadrant 4. Draw the reference triangle. If sin is -12/13, then the hypotenuse of the ref. triangle is 13. Which area of the triangle is 12? what's the size of the third area (you will could calculate this) With the lengths of all 3 facets of the triangle labelled, you may genuinely record the values of all the trig purposes.
If D were positive that would be the answer. √3/2