Assume the answer is x. Now think about: what will happen, if we were to add 20 to x, and then take the square root? Well, we get a number of exactly the same 'description' as the original x. That is, x. In other words, we just constructed the equation x = √(20+x).
With the standard issues concerning radic equations about signs in mind, this can be (carefully) squared into
If its the square of 20 it would be 400 and the square root of 20 is 4 on the square root of 5. (sorry idk the square root symbol) So the answer would be infiniti, I mean it would be multiples of 400 plus multiples of 4 on the square root of 5 (8 on the square root of 5, 12 on the square root of 5 and so on).
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Assume the answer is x. Now think about: what will happen, if we were to add 20 to x, and then take the square root? Well, we get a number of exactly the same 'description' as the original x. That is, x. In other words, we just constructed the equation x = √(20+x).
With the standard issues concerning radic equations about signs in mind, this can be (carefully) squared into
x^2=20+x
x^2 - x - 20 = 0
x = 5.
(The negative root is obviously false).
If its the square of 20 it would be 400 and the square root of 20 is 4 on the square root of 5. (sorry idk the square root symbol) So the answer would be infiniti, I mean it would be multiples of 400 plus multiples of 4 on the square root of 5 (8 on the square root of 5, 12 on the square root of 5 and so on).
Hope this answers ur question?
sqrt(20 + sqrt(20 + sqrt( 20 + ...
I'm not sure if the sum to infinity of this exists.
plug it into your calculator. . . your explanation is kind of foggy