What is the total resistance of a series circuit with 3 resistors having the values of 10kΩ, 30kΩ, and 50kΩ?
If the circuit mentioned in the Question above has 2 mA of current flowing through the 30kohms resistor, what is the total voltage drop for the circuit?
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Total R
10 k + 30 k + 50 k = 90 k
Total Voltage
Vt = 90 k 2ma = 18 volts
sequence resistors basically convey at the same time (upload at the same time) because of the fact the present has to combat its way through one and then yet another. the present could be the comparable through all resistors, because of the fact there is in basic terms one direction. So the present, I = V/R, the place R is basically the sum.
series resistors basically convey at the same time (upload at the same time) by way of fact the present has to combat its way via one and then yet another. the present would be a similar via all resistors, by way of fact there is largely one direction. So the present, I = V/R, the place R is basically the sum.
Add 'em up. If the current at one point is 2 mA, then the current at all points is 2 mA, and Ohms' Law will give the volts...E=R*I