please try to have solid explanation behind the answer. trying to learn it for final, thank you.
The equation to calculate pH when you know [H3O+] is:
pH = -log [H3O+]
substitute:
pH = - log ( 4*10^-13)
pH = 12.40
pH = - log [H3O+] = - log (4X10^-13) = 12.4
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The equation to calculate pH when you know [H3O+] is:
pH = -log [H3O+]
substitute:
pH = - log ( 4*10^-13)
pH = 12.40
pH = - log [H3O+] = - log (4X10^-13) = 12.4