What is the molarity of NO3– in a 250.0 mL solution that contains 50.0 g of Al(NO3)3 (213 g/mol)?
I can find the molality of Al(NO3)3. How do I convert that to the molality of NO3-?
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I can find the molality of Al(NO3)3. How do I convert that to the molality of NO3-?
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First find how many moles 50 g is. 50/213 = .23474
Now that you have that in moles, find the molarity. .23474/.25 = .93896
Then multiply that by how many NO3 moles you have (3 because you will have 3 times as may NO3 moles per liter than Al(NO3)3 moles per liter) .93896 * 3 = 2.82