What is the molar mass of the solute? (R = 0.08206 L×atm/mol×K)?

A solution is prepared by dissolving 5.88 g of an unknown nonelectrolyte in enough water to make 0.355 L of solution. The osmotic pressure of the solution is 1.21 atm at 27 °C. What is the molar mass of the solute? (R = 0.08206 L×atm/mol×K)

Answer

a.

30.3 g/mol

b.

0.00297 g/mol

c.

337 g/mol

d.

175 g/mol

e.

42.5 g/mol

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