Differentiate and equate to zero
Hence
h'(t) = -32t + 14 = 0
32t = `4
t = 14/32
t = 7/16 Is the time to reach max. height
h(7/16) = -16(7/16)^2 + 14(7/16)
h(7/16) = -49/16 + 6 1/8
h(7/16) = 3 1/16 = 3.0625 = 3.063 (nearest thousandth).
h (t) = - 16 t² + 14 t
h ` (t) = - 32 t + 14 = 0 for turning point.
t = 14 / 32 = 7 / 16
h (7/16) = -16 [ 49/256 ] + 98/16
h (7/16) = - 49/16 + 98/16 = 49/16
Max height = 3•0625
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Answers & Comments
Differentiate and equate to zero
Hence
h'(t) = -32t + 14 = 0
32t = `4
t = 14/32
t = 7/16 Is the time to reach max. height
Hence
h(7/16) = -16(7/16)^2 + 14(7/16)
h(7/16) = -49/16 + 6 1/8
h(7/16) = 3 1/16 = 3.0625 = 3.063 (nearest thousandth).
h (t) = - 16 t² + 14 t
h ` (t) = - 32 t + 14 = 0 for turning point.
t = 14 / 32 = 7 / 16
h (7/16) = -16 [ 49/256 ] + 98/16
h (7/16) = - 49/16 + 98/16 = 49/16
Max height = 3•0625