Q = m x c x delta t
47.6 kJ = 1.110 kg x 4.18 x delta t
delta t = 47.6 / (1.110 x 3.18).
delta t = 10.26 oC
So final temp is 19.9 + 10.26 = 30.2 oC
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Verified answer
Q = m x c x delta t
47.6 kJ = 1.110 kg x 4.18 x delta t
delta t = 47.6 / (1.110 x 3.18).
delta t = 10.26 oC
So final temp is 19.9 + 10.26 = 30.2 oC