Verified answer

Just subtract the contrasting Ys and Xs

(Y2-Y1)

(-6-2)

Y=(-8)

(X2-X1)

(1+5)

X=6

Think of it as a triangle, with the base as 6, height as -8.

Use the Pythagorean Formula and solve for c

a^2+b^2=c^2

(6)^2+(-8)^2=c^2

36+64=c^2

100=c^2

square root(100)=c

10 units = C

The answer is D

The distance between two points is

sqrt ((y2 - y1)^2 + (x2 - x1)^2)) = sqrt ((2 - -6)^2 + (-5 -1)^2)) = sqrt 100 = 10

z^2 = (x1 - x2)^2 + (y1 - y2)^2.

z^2 = (1+ 5)^2 + (- 6 - 2)^2

z^2 = 36 + 64 = 100

z = 10

Answer is D

D.10 units is your answer

change in y, -6 to 2, is 8

change in x, 1 to -5, is -6

so far that's what you'd do to get slope, which is 8/-6 = -4/3

for distance, square 'em, add 'em, root 'em.

d = √(8² + 6²) = √100 = 10

(1, –6) and (–5, 2)

sqrt((-5-1)^2+(2+6)^2)

=sqrt(36+64)=sqrt(100)=10

therefore, the final answer is d