Verified answer

At STP 1 mol of gas occupies 22.4 L. So what we have to do is find the new volume of gas under the conditions you describe.

STP

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V = 22.4 L

P = 1 Atm

T = 0 + 273 = 273

Given conditions

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V1 = ???

P1 = 1.5 atm

T1 = 264 oK

V*P/T = V1*P1/T1

22.4 * 1 / 273 = V1 * 1.5 / 264

V1 = 22.4 * 1 * 264/(273 * 1.5)

V1 = 14.44 L

Now we need to find out the molar mass of H2S

2*1 + 32 = 34

1 mole of H2S has a mass of 34 grams / mol

The density is mass / Volume

d = 34/ 14.44 = 2.35 grams /L

ok jennifer lopez... start with these 2 equations...

(1).. PV = nRT

(2).. n = mass / mw

substitute and rearranging...

PV = (mass / mw) RT

(mass / V) = mw x P / (RT)

since density = mass / V...

density = mw x P / (RT)

solving...

density = (34.08g/mol) x (1.5atm) / ((0.08206 Latm/molK) x (264K))

density = 2.4 g/L