For H2SO4, Ka1 is very large and Ka2 = 1.2 × 10−2.
1. 0.0098 M
2. 0.029 M
3. 0.035 M
4. 0.012 M
5. 0.017 M
6. 0.0086 M
7. 0.10 M
I would really appreciate the help
H2SO4(aq) --> H^+(aq) + HSO4^-(aq)
[H^+] due to this ionization = 0.100 M
HSO4^- + H2O(aq) <=> H3O^+(aq) + SO4^2-(aq)
Ka2 = [H3O^+][SO4^2-]/[HSO4^-] = 1.2 x 10^-2
Let [H3O^+] = 0.100 + x, [SO4^2-] = x, and [HSO4^-] = 0.100 - x
(0.100 + x)(x)/(0.100 - x) = 1.2 x 10^-2
0.100x + x^2 = (1.2 x 10^-2)(0.100 - x) = 1.2 x 10^-3 - 1.2 x 10^-2(x)
x^2 + 0.112x - 1.2 x 10^-3 = 0
Now, solve the quadratic equation. Let a = 1, b = 0.112, and c = -0.0012
See the link for a solver.
x = 0.0098 M The correct choice is 1.
Hope this is helpful to you. JIL HIR
Copyright © 2024 1QUIZZ.COM - All rights reserved.
Answers & Comments
Verified answer
H2SO4(aq) --> H^+(aq) + HSO4^-(aq)
[H^+] due to this ionization = 0.100 M
HSO4^- + H2O(aq) <=> H3O^+(aq) + SO4^2-(aq)
Ka2 = [H3O^+][SO4^2-]/[HSO4^-] = 1.2 x 10^-2
Let [H3O^+] = 0.100 + x, [SO4^2-] = x, and [HSO4^-] = 0.100 - x
(0.100 + x)(x)/(0.100 - x) = 1.2 x 10^-2
0.100x + x^2 = (1.2 x 10^-2)(0.100 - x) = 1.2 x 10^-3 - 1.2 x 10^-2(x)
x^2 + 0.112x - 1.2 x 10^-3 = 0
Now, solve the quadratic equation. Let a = 1, b = 0.112, and c = -0.0012
See the link for a solver.
x = 0.0098 M The correct choice is 1.
Hope this is helpful to you. JIL HIR