I have ∥u∥ = sqrt(162) but when i try to enter V as (-12)/sqrt(162) it tells me its wrong...what did I do wrong?
Magnitude of u = sqrt(162). This is correct.
V = (3, -3, -12)/sqrt(162) << I guess you simply forgot the x and y components
or V = (3/sqrt(162), -3/sqrt(162), -12/sqrt(162)) if you wish to express it in component form.
You went wrong in not appreciating that u is a 3-dimensional vector. With reference to 3 mutually perpendicular axes, x, y and z, each contains unit vectors i, j and k respectively.
Therefore, u = 3i - 3 j - 12k.
|u| = √(3² + 3² + 12²) = √(9 + 9 + 144) = √162.
Hence, u / |u| = (3i - 3 j - 12k) / √162.
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Answers & Comments
Magnitude of u = sqrt(162). This is correct.
V = (3, -3, -12)/sqrt(162) << I guess you simply forgot the x and y components
or V = (3/sqrt(162), -3/sqrt(162), -12/sqrt(162)) if you wish to express it in component form.
You went wrong in not appreciating that u is a 3-dimensional vector. With reference to 3 mutually perpendicular axes, x, y and z, each contains unit vectors i, j and k respectively.
Therefore, u = 3i - 3 j - 12k.
|u| = √(3² + 3² + 12²) = √(9 + 9 + 144) = √162.
Hence, u / |u| = (3i - 3 j - 12k) / √162.
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