I Know it's an "imaginary" quadratic formula. Using the Imaginary i, what do you get?
x² - 2x + 17 = 0.
Using the quadratic formula, we have:
x = ( 2 ± √((-2)² - 4(1)(17)) ) / 2(1)
= ( 2 ± √(4 - 68) ) / 2
= ( 2 ± √(-64) ) / 2
= (2 ± 8i) / 2
= 1 ± 4i.
(equivalently, x = 1 + 4i or x = 1 - 4i.)
[2 (plus or minus) sqrt(64) * (i)]/2
(2+8i)/2 or (2-8i)/2
1+4i or 1-4i
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Answers & Comments
x² - 2x + 17 = 0.
Using the quadratic formula, we have:
x = ( 2 ± √((-2)² - 4(1)(17)) ) / 2(1)
= ( 2 ± √(4 - 68) ) / 2
= ( 2 ± √(-64) ) / 2
= (2 ± 8i) / 2
= 1 ± 4i.
(equivalently, x = 1 + 4i or x = 1 - 4i.)
[2 (plus or minus) sqrt(64) * (i)]/2
(2+8i)/2 or (2-8i)/2
1+4i or 1-4i