i is the square root of -1. so you'll have to square both of these. In this example: -3*-3 =9 and sqrt(-1)*sqrt(-1) =-1 . So now take 9*-1 to get a final answer of -9
Of course if you think of it as the distance from the origin (0,0i) to (0,-3i) on the complex plane, it's obviously just 3, as confirmed by the formula.
Use pythagoras to find the hypotenuse and ie. the longest side which is the magnitude when you have numbers in both vertical and horizontal components, like -3i+2j.
Also the magnitude is just the positive value of the length of the line/vector, just thought i'd mention.
Answers & Comments
The magnitude is 3.
√(0^2 + (-3)^2) =
√(0 + 9) =
√9 =
3
-
Magnitude is 3
|-3i| = |-3| x |i| = 3 x 1 = 3.
The magnitude is '3' usuallu written as |3|.
(-3)^2 = 9. Don't listen to the idiots who says it's 3.
i is the square root of -1. so you'll have to square both of these. In this example: -3*-3 =9 and sqrt(-1)*sqrt(-1) =-1 . So now take 9*-1 to get a final answer of -9
Remember:
|a + bi| = √(a² + b²)
In this case, a=0, b=-3
|-3i| = √[(-3)²]
= √9
= 3
Of course if you think of it as the distance from the origin (0,0i) to (0,-3i) on the complex plane, it's obviously just 3, as confirmed by the formula.
It is just 3.
Use pythagoras to find the hypotenuse and ie. the longest side which is the magnitude when you have numbers in both vertical and horizontal components, like -3i+2j.
Also the magnitude is just the positive value of the length of the line/vector, just thought i'd mention.
3
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