Verified answer

Well, g o f(-2) can also be written as g(f(-2)). It means that you take the value you got by substituting -2 into the function f(x) and put that into g(x).

f(-2) = 3 - 2(-2) = 3 + 4 = 7

Now, you take that value you just got and use it in the function g(x).

g(7) = √7 <--- The square root of 7 is irrational, so you're done.

Method I

g(x) = √x and f(x) = 3 - 2x

so (g o f)(x) = √(3-2x)

Now (g o f)(-2) = √(3-2(-2))

= √(3+4) = √7

Method II

first find f(-2) and then put the value in g(x)

=> f(-2) = 3-2(-2) = 3+4 = 7

=> (g o f)(-2) = √7