Verify The Following Identities Tan(x+y) ÷ cot(x-y) = tan2x-tan2y÷1-tan2xtan2y?
help me please!
Tan(x+y) ÷ cot(x-y) = tan2x-tan2y÷1-tan2xtan2y
Cos2x = cos4x-sin4x
Cos5x-cos3x ÷ cos5x+cos3x = -tanxtan
More Questions From This User See All
Answers & Comments
Verified answer
... LHS
= tan (x+y) / cot (x-y)
= tan (x+y) · tan (x-y)
= [ ( tan x + tan y ) / ( 1 - tan x tan y ) ] • [ ( tan x - tan y ) / ( 1 + tan x tan y ) ]
= [ ( tan x + tan y )( tan x - tan y ) ] / [ ( 1 - tan x tan y )( 1 + tan x tan y ) ]
= ( tan² x - tan² y ) / ( 1 - tan² x tan² y )
= RHS.
................. Hence, the result.
..........................................................................................................................................
................. Happy To Help !
...............................................................................................................................................
To coach 2/tanx+cotx=sinx LHS 2/tanx+cotx=2cosx/sinx +cosx/sinx =3cosx/sinx =3cotx The given equation would not seem to be identity positioned x= 40 5 ° LHS =2/tanx+cotx=2/tan45°+cot45°= 2/a million+a million=3 and sinx < a million