can some explain to me how to solve this please!! this is trigonometry btw
A curve is symmetrical about the x-axis if you replace y by -y in the equation
and arrive at the original equation. Here you get -y=3x ²-10 giving y=10-3x ² which is not
the same as y=3x ²-10, so curve is not symmetrical about the x-axis.
A curve is symmetrical about the y-axis if you replace x by -x and arrive at the original equation.
Here y=3(-x)²-10=3x²-10 so curve is symmetrical about the y-axis.
A curve has point symmetry about the origin (0,0) if you replace x by -x and y by -y
and arrive at the original equation. Here, (-y)=3(-x)²-10 giving y=10-3x² which is different
from y=3x ² -10.
If you graph the curve y=3x²-10 you can verify the above.
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Answers & Comments
A curve is symmetrical about the x-axis if you replace y by -y in the equation
and arrive at the original equation. Here you get -y=3x ²-10 giving y=10-3x ² which is not
the same as y=3x ²-10, so curve is not symmetrical about the x-axis.
A curve is symmetrical about the y-axis if you replace x by -x and arrive at the original equation.
Here y=3(-x)²-10=3x²-10 so curve is symmetrical about the y-axis.
A curve has point symmetry about the origin (0,0) if you replace x by -x and y by -y
and arrive at the original equation. Here, (-y)=3(-x)²-10 giving y=10-3x² which is different
from y=3x ² -10.
If you graph the curve y=3x²-10 you can verify the above.