Use the Law of Cosines to find the angle α between the vectors.
(Assume 0° ≤ α ≤ 180°.)
v = i + j, w = 5i − 5j
=>
for v = i + j
V = √2
for w = 5i − 5j
W = 5√2
VW = √[(1+5)^2 + (5-1)^2] = 2√13
(2√13)^2 = (√2)^2+(5√2)^2 - 2(√2)(5√2)cos α
cos α = 0 / [-2(√2)(5√2)] = 0
α = 90°
Answer
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=>
for v = i + j
V = √2
for w = 5i − 5j
W = 5√2
VW = √[(1+5)^2 + (5-1)^2] = 2√13
(2√13)^2 = (√2)^2+(5√2)^2 - 2(√2)(5√2)cos α
cos α = 0 / [-2(√2)(5√2)] = 0
α = 90°
Answer