Determine (1 - i raiz de 3)^5
Determine (1 - i√3)^5
Ola Cicero
z = (1 - √3i)
¦z¦ = √(1+3) = 2
tg(α) = sen(α)/cos(α)
tg(α) = -√3/1 = -√3
α = -60
z = 2*(cos(-60) + isen(-60))
z⁵ = 2⁵*(cos(-300) + isen(-300))
z⁵ = 32*(1/2 + i√3/2) = 16*(1 + √3i)
pronto
Matemática
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Answers & Comments
Ola Cicero
z = (1 - √3i)
¦z¦ = √(1+3) = 2
tg(α) = sen(α)/cos(α)
tg(α) = -√3/1 = -√3
α = -60
z = 2*(cos(-60) + isen(-60))
z⁵ = 2⁵*(cos(-300) + isen(-300))
z⁵ = 32*(1/2 + i√3/2) = 16*(1 + √3i)
pronto
Matemática