Two resistors with R1 = 1150 Ω and R2 = 4450 Ω are connected in series as shown in the figure below.?
(a) If the battery emf is = 18 V, what is the current through each of the resistors?
(b) What is the equivalent resistance of the two resistors?
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Answer b first.
Rt = R1 + R2
Rt = 1150 + 4450 ohms
Rt = 5600 ohms
The current is the same in both resistors.
I = E/R
I = 18 / 5600 = 3.21 * 10^-3 amperes or more commonly 3.21 ms