If X = 3 sin Θ, write the following expression in terms of just X.
(Θ/3)+(sin 2Θ/6)
(Θ/3)+(sin 2Θ/6) = 1/3*arcsin(x/3) + (x/3)(√(1 - (x^2/9))/3
= 1/3*arcsin(x/3) + x√(9 - x^2)/27
X = 3 sin (O)
X/3 = sin (O)
inverse sin(X/3) = O
(O/3) + sin (2O/6)
(O/3) + sin (1O/3)
((inverse sin (X/3))/3) + sin ((inverse sin (X/3)/3)
Got you started... dont actually know how to finish
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Verified answer
(Θ/3)+(sin 2Θ/6) = 1/3*arcsin(x/3) + (x/3)(√(1 - (x^2/9))/3
= 1/3*arcsin(x/3) + x√(9 - x^2)/27
X = 3 sin (O)
X/3 = sin (O)
inverse sin(X/3) = O
(O/3) + sin (2O/6)
(O/3) + sin (1O/3)
((inverse sin (X/3))/3) + sin ((inverse sin (X/3)/3)
Got you started... dont actually know how to finish