Trig - find polar coordinates: r = 1-2 cosθ?
find polar coordinates in the form (r, theta) of two points which satisfy this equation.
I am studying for a final that is next week and need a little help with the concepts.
The coordinates I can up with (1, pi) and (3, pi). Are these correct? If not, can you explain how I would get to the correct coordinates?
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Just pick a value for theta and go with it
For instance: t = pi/4
r = 1 - 2 * cos(pi/4) = 1 - 2 * (sqrt(2)/2) = 1 - sqrt(2)
(1 - sqrt(2) , pi/4) would be a coordinate
t = pi/2
r = 1 - 2 * cos(pi/2) = 1 - 0 = 1
(1 , pi/2)
t = pi/6
r = 1 - 2 * cos(pi/6) = 1 - 2 * sqrt(3)/2 = 1 - sqrt(3)
(1 - sqrt(3) , pi/6)
It should be (-1, pi/2) second is correct.
sparkling up the given equations and get rid of r with the help of putting the value of r=2sin(?) in the 2d equation r=2sin(2?) which will supply 2sin(?)=2sin(2? or sin(?)=sin(2?. little want a million/2 attitude id sin(2?=2sin?cos? and get a million=2cos? which will will supply ?=60 degree. So at 60 degree attitude the given polar equations will intersect eachother