To start her lawn mower, Julie pulls on a cord that is wrapped around a pulley. The pulley has a moment of inertia about its central axis of I = 0.570kg⋅m2 and a radius of 6.00cm . There is an equivalent frictional torque impeding her pull of τf = 0.500m⋅N .
Part A: To accelerate the pulley at α = 4.40rad/s2 , how much torque does Julie need to apply to the pulley?
Part B: How much tension must the rope exert?
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Verified answer
Torque = I.α = 0.57 × 4.4 = 2.51 N.m
tension in rope = 2.51/0.06 = 41.8 N
Part A: don't forget to add in the 0.500m⋅N
Part B: take part A and divide by radius in meters