Verified answer

√-8 + 2√-50

= √[4*(-2)] + 2√[25*(-2)]

= √4* √-2 + 2 * √25 * √-2

= 2*√-2 + 2 * 5 * √-2 [because √4 = 2 and √25 = 5]

= 2*√-2 + 10 * √-2

= (2 + 10) *√-2

= 12 * √-2

Ans: 12 * √-2

√-8 = 2√2 i and 2√-50 =2√(-2×5×5) =2×5√2 i= 10√2 i

√-8 + 2√-50 =2√2 i + 10√2 i= 12√2 i

√-8 + 2√-50

= √(8)i and 2√(50)i

= 2√(2)i and 10√(2)i

= 12√(2)i

√-8 + 2√-50 = 2√-2 +2(5)√-2 = 12√-2 = 12i√2

√(-8) + 2√(-50)

√(-1*8) + 2√(-1*50)

√(-1*4*2) + 2√(-1*25*2)

√-1√4√2 + 2√-1√25√2

i*2√2 + 2*i*5√2

2i√2 + 10i√2

(2i + 10i)√2

12i√2

2√2 i + 2(5√2) i

2√2 i + 10√2 i

12√2 i

√(-8) + 2√(-50)

= √(2^2 * i^2 * 2) + 2√(5^2 * i^2 * 2)

= 2i√2 + 2(5)(i)√2

= 2i√2 + 10i√2

= (2i + 10i)√2

= 12i√2

2√2 i + 2(5√2) i

2√2 i + 10√2 i

12√2 i or √-288)

√-8+2√-50=

√8i^2+2√50i^2=

i√8+2i√50=

i2√2+2*i*5√2=

i√2(2+10)=12i√2

0 + 16.97i